Persamaan garis yang melalui titik (4, -3) dan tegak lurus dengan garis 4y - 6x +10 = 0 adalah a. 2x + 3y = 1 b. 2x + 3y = -1 2x - 3y = -1 d. 2x - 3y = 1 c. lalui titik (21) dan
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Verified answer
( 4 , -3 ) --> x = 4 dan y = -3
Persamaan garis tegak lurus
[tex]4y - 6x + 10 = 0 \\ 6y + 4x = 6( - 3) + 4(4) \\ 4x + 6y = - 18 + 16 \\ 4x + 6y = - 2 \\ - - - - - - - \div 2 \\ 2x + 3y = - 1 \: (b)[/tex]
pers garis titik (4 , -3) :
4y - 6x + 20 = 0
6y + 4x = (6 × (-3) + (4 × 4)
6y + 4x = -18 + 16
6y + 4x = -(18 - 16)
6y + 4x = -2 => (bagi 2)
(6/2)y + (4/2)x = (-2/2)
3y + 2x = -1