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=-3/6=-1/2
pers garis
y-y1=m(x-x1)
y-5=(-1/2)(x+3)
2y-10=-x-3
x+2y-7=0
memotong sumbu y(x=0)
2y=7
y=7/2
titik (0,7/2)
( y - 5) / (2 - 5)= ( x - (-3) ) / (3 - (-3))
( y - 5) / (-3)= ( x +3)/ 6
6 ( y - 5) = - 3 ( x +3 )
6y - 30 = -3x - 9
6y = -3x -9 +30
6y = -3x + 21
2y = -x + 7
memotong di sumbu y berarti x=0
lalu disubtitusikan ke persamaan
2y = -x + 7
2y = 0 + 7
y = 7/2
memotong dititik (0, 7/2)