[tex] \tt \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
[tex] \tt \frac{y - 4}{1 - 4} = \frac{x - 3}{8 - 3} [/tex]
[tex] \tt \frac{y - 4}{ - 3} = \frac{x - 3}{5} [/tex]
5(y - 4) = -3(x - 3)
5y - 20 = -3x + 9
3x + 5y - 20 - 9 = 0
3x + 5y - 29 = 0
Jawaban B.
@BeruangGemoy :•
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Verified answer
[tex] \tt \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
[tex] \tt \frac{y - 4}{1 - 4} = \frac{x - 3}{8 - 3} [/tex]
[tex] \tt \frac{y - 4}{ - 3} = \frac{x - 3}{5} [/tex]
5(y - 4) = -3(x - 3)
5y - 20 = -3x + 9
3x + 5y - 20 - 9 = 0
3x + 5y - 29 = 0
Jawaban B.
@BeruangGemoy :•