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y = m1x + c
3x - 8y - 22 = 0
3x - 22 = 8y
y = (3x - 22)/8
y = 3x/8 - 22/8
m1 = 3/8
tegak lurus :
m1 × m2 = -1
3/8 × m2 = -1
m2 = -1 × 8/3
m2 = -8/3
(x1, y1) = (-3, 2)
Persamaan garis yang melalui 1 titik :
y - y1 = m2(x - x1)
y - 2 = -8/3 (x - (-3)) (× 3)
3(y - 2) = -8(x + 3)
3y - 6 = -8x - 24 (semuanya pindah ke ruas kiri)
8x + 3y - 6 + 24 = 0
8x + 3y + 18 = 0
maaf kalau salah
semoga membantu