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M1 = -x/y
M1 = -4/5
Syarat tegak lurus
M1.M2 = -1
-4/5 . M2 = -1
M2 = -1/-4/5
M2 = -5/-4
M2 = 5/4
Y - Y1 = M(X - X1)
Y - 5 = 5/4(X - 2)
Y - 5 = 5/4X - 5/2
KALI 4 KEDUA RUAS
4Y - 20 = 5X - 10
5X - 4Y = -10