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y = mx + c
2x + 3y = 6
3y = -2x + 6
y = -2/3x + 2
m = -2/3
karena tegak lurus, maka :
m1 . m2 = -1
-2/3 . m2 = -1
m2 = -1 / (-2/3)
m2 = 3/2
y - b = m (x - a)
y - 3 = 3/2(x -(-2))
y - 3 = 3/2(x + 2)
y - 3 = 3/2x + 3
y = 3/2x + 3 + 3
y = 3/2x + 6
atau
2y = 3x + 12
atau
2y - 3x - 12 = 0
atau lagi
2y - 3x = 12
3y = - 2x :3
=
y =
y - y1 = m.( x - x1 )
y - 3 = . (x - (-2) ×2
2y - 6 = . (x + 2)
2y - 6 = -3.(x + 2)
2y - 6 = -3x - 6
2y + 3x - 6 + 6 = 0
2y + 3x + 0 = 0