Question

Persamaan garis yang melalui titik (-2,3) dan tegak lurus garis 2×+3y=6 adalah?

Answer 1

3y = - 2x + 6
y = (-2/3)x + 2
m₁ = - 2/3
m₂ = 3/2

Persamaan Garisnya:
y - b = m(x - a)
y - 3 = (3/2)(x + 2)
2y - 6 = 3x + 6
3x - 2y + 12 = 0

Answer 2

2x + 3y = 6
y= -2/3
tegak lurus
m1.m2 = -1
-2/3.m2 = -1
m2 = 3/2

y-y1 = m(x-x1)
y-3 = 3/2(x+2)
y-3 = 3/2x + 3
y = 3/2x + 6
2y = 3x + 12