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Ax + By + c = 0
gradien (m) = -a/ b
2x - 3y + 7 = 0
m1 = -2/(-3) = 2/3
karena persamaan garis tegak lurus maka berlaku
m1 . m2 = -1
m2 = -1/m1
m2 = -1/(2/3)
m2 = -3/2
persamaan garis lurus di titik(x1, y1) bergradien m2
gs : (y -y1) = m(x -x1)
y - 3= -3/2 (x -2)
y - 3 = -3/2x + 3
y = -3/2x +6
2y = -3x + 12