Question

Persamaan garis yang melalui titik (1,6) dan tegak lurus terhadap garis 7x-y-20=0 adalah....

Answer 1

Titik (1,6)

tegak lurus garis 7x-y-20=0
y=7x-20
didapat m = 7

y-y1 = m ( x-x1)
y-6=7(x-1)
y=7x-1

Answer 2

7x-y-20 = 0
-y = -7x + 20
 y =  7x - 20
y = mx + c
y = 7x - 20
m = 7

y-y1 = m(x-x1)
y-6 = 7(x-1)
y-6 = 7x -7
-7x+y-6+7 = 0
-7x+y+1 = 0║x -1║
7x-y-1 = 0