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Verified answer
Gradien yg melewati titik (-4,5) dan (-3,3)m = (y2 - y1) / (x2 - X1)
m = (3 - 5) / (-3 - (-4)
m = - 2 / (- 3 + 4)
m = - 2 / 1
m = - 2
gradien tegak lurus dg m = 2
m1 . m2 = - 1
2 . m2 = - 1
m2 = - ½
pers garis yg melewati (0,6)
y - y1 = m (x - X1)
y - 6 = - ½ (x - 0)
y = - ½ x + 6 (dikalikan 2 utk menghilangkan penyebut)
2y = - x + 12
2y + x = - 12