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syarat tegak lurus m1.m2 = -1
m1 = -3.5 maka m2 = 5/2
persamaan garis dengan m = 5/2 melalui titik (2,5)
y-y1 = m ( x - x1)
y -5 = 5/2 (x - 2)----> kalikan 2
2y - 10 = 5x - 10
2y - 5x = 0