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Verified answer
Materi : Persamaan GarisKelas : VIII SMP
2x - 3y + 8 = 0
-3y = -2x - 8
y = 2x/3 + 8/3
m₁ = 2/3
m₂ = -3/2
Syarat Tegak Lurus :
⇒ m₁ . m₂ = -1
y - y₁ = m ( x - x₁ )
y - 2 = -3/2 ( x + 3 )
y - 2 = -3x/2 - 9/2
y = -3x/2 - 9/2 + 4/2
y = -3x/2 - 5/2
Bentuk Lain :
⁺ 2y = -3x - 5
⁺ 2y + 3x + 5 = 0
Verified answer
2x-3y +8=0 dan melalui titik(-3,2)2x-3y +8=0
m1 = -a/b = -2/-3 = 2/3
Karena trgak lurus, maka
m1.m2 = -1
2/3 . m2 = -1
m2 = -3/2
Persamaan garis melalui titik (-3,2)
Y - Y1 = m(X - X1)
Y - 2 = -3/2(X + 3)
Y - 2 = -3/2X - 9/2
2Y - 4 = -3X - 9
3x + 2y = -5