Question

Persamaan garis melalui titik (-4,-2) dan tegak lurus dengan garis 2x + 6y - 12 = 0 adalah.....

#need Trmksh

Answer 1

M = 3
y-b=m(x-a)
y-(-2)=3(x-(-4))
y+2=3(x+4)
y= 3x+12-2
y=3x+10

Answer 2

2x + 6y - 12 = 0
               6y = -2x + 12
                 y = -2/6x + 2
                 y = -1/3x + 2

m₁ = -1/3

 m₁ × m₂ = -1
-1/3 × m₂ = -1
          m₂ = 3

  (y - y₁) = m(x - x₁)
(y - (-2)) = 3(x - (-4))
    y + 2 = 3(x + 4)
    y + 2 = 3x + 12
          y = 3x + 12 - 2
          y = 3x + 10