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gradien persamaan garis yang sejajar = m2 = b/a = -5/2
y-y1 = m2(x-x1)
y-4 = -5/2 (x-(-3))
2(y-4) = -5(x+2)
2y - 8 = -5x - 10
5x + 2y - 8 + 10 = 0
5x + 2y + 2 = 0 atau 5x + 2y = -2
Jadi persamaan garis yang melalui titik ( -3,4) dan tegak lurus garis 2x-5y+7=0 adalah 5x + 2y + 2 = 0 atau 5x + 2y = -2
5x+2y= 5(-3) + 2(4)
5x+3y=7 atau 5x+3y-7=0