Question

Persamaan garis melalui titik (2,-3) dan sejajar garis 2x-3y+5=0 adalah?
kasih caranya ya

Answer 1

2x - 3y + 5 = 0
-3y = -2x - 5
3y = 2x + 5
y = 2/3x + 5

y = mx + c
m = 2/3

y - b = m(x - a)
y - (-3) = 2/3(x - 2)
y + 3 = 2/3x + 4/3
kalikan 3

3y + 9 = 2x + 4
3y - 2x + 9 - 4 = 0
3y - 2x + 5 = 0

atau

2x - 3y - 5 = 0

atau

3y = 2x - 5

Answer 2

2x - 3y + 5 = 0
-3y = -2x - 5
y = 2/3 x - 5

Persamaan Garis sejajar =
y - y1 = m (x - x1)
y + 3 = 2/3 (x - 2)
y + 3 = 2/3x - 4/3
(semuanya dikali 3)
3y + 9 = 2x - 4
3y = 2x - 4 - 9
3y = 2x - 13
atau
3y - 2x = 13
atau
3y - 2x - 13 = 0