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m=-3/1
m=-3
y-y1=m(x-x1)
y+1=-3(x-3)
y+1=-3x-9
y+3x=-9-1
y+3x=-10
y+3x+10=0
3x + y - 2 = 0
rumusnya -x/y
jadi gradiennya (m) = -3/1 = -3
persamaan garis lurus sejajar (m1 = m2) melalui titik (3, -1)
a = 3; b = 2
y - a = m ( x - b )
y - 3 = -3 ( × - (-1))
y - 3 = -3x + 3
y + 3× = 3 + 3
y + 3× = 6 atau y = -3× + 6 atau y + 3× -6 = 0