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y+2 = -5(x-3)
y+2 = -5x+15
5x+y = 15-2
5x+y = 13
atau
5x+y-13 = 0
y = mx+c
atau bisa dengan yang ini
(y-y1)=m(x-x1)
A(3,-2)
maka
x1 = 3
y1=-2
masukkan ke rumus
(y-y1)=m(x-x1)
(y-[-2])=(-5)(x-3)
y+2= -5x+15
y= -5x + 13
sudaaah^^ maaf kalau salah.