m = Δy / Δx
m = (0+5) / (10-0) = 1/2
y-y1 = m(x-x1)
y+5 = 1/2 (x-0)
2(y+5) = x
2y+10 = x
x-2y = 10
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Verified answer
m = Δy / Δx
m = (0+5) / (10-0) = 1/2
y-y1 = m(x-x1)
y+5 = 1/2 (x-0)
2(y+5) = x
2y+10 = x
x-2y = 10
Verified answer
Y-y1 /y2-y1=x-x1/x2-x1y-(-5)/0-(-5)=x-0/10-0
y+5 /0+5 =x-0/10
y+5 / 5 =x-0/10
perkalian silang
y+5(10)=x-0(5)
10y+50=5x-0
10y =5x-50
y =5/10x-50/10
y =1/2 x-5