Question

Persamaan garis k yang melalui titik (-1 , 5) dan tegak lurus dg garis , 4x - 7y+28 =0 adl
a. 4x + 7y - 31 =0
b. 4y - 7x-13 = 0
c. 4y - 7x-27 = 0
d. 4y + 7x-27 = 0
e. 4y + 7x-13 = 0

Answer 1

4x-7y+28=0
-7y=-4x0-28
y=-4x/-7 - 28/-7
m1=4/7
m1.m2=-1
4/7.m2=-1
m2=-1.7/4 = -7/4

y-y1=m(x-x1)
y-5=-7/4(x+1)
y-5=-7/4x - 7/4 --> semua dikali 4
4y-20=-7x -7
4y=-7x-7+20
4y=-7x+13
jadi, 4y+7x-13=0 (E)