Penjelasan dengan langkah-langkah:
a.y-y1 = m(x-x1)
y-6=3 (x-(-2)
y-6=3(x+2)
y-6=3x+6
y=3x+6+6
y=3x+12
b.y-y1 = m(x-x1)
y-3 = 3/2 (x-1)
2(y-3)=3(x-1)
2y-6=3x-3
2y-3x=3
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Verified answer
Penjelasan dengan langkah-langkah:
a.y-y1 = m(x-x1)
y-6=3 (x-(-2)
y-6=3(x+2)
y-6=3x+6
y=3x+6+6
y=3x+12
b.y-y1 = m(x-x1)
y-3 = 3/2 (x-1)
2(y-3)=3(x-1)
2y-6=3x-3
2y-3x=3