Question

Persamaan dari garis lurus yang melewati titik (4,1) dan (-2,3) adalah...

Answer 1

Y-y1/y2-y1 = x-x1/x2-x1
y-1/3-1= x-4/-2-4
y-1/2=x-4/-6
-6 (y-1)=2 (x-4)
-6y+6=2x-8
-2x-6y+6+8=0
-2x-6y+14=0
x+3y-7=0

Answer 2

Y-y1/y2-y1 = x - x1/x2-x1
y - 1/3 -1 = x - 4/-2-4
y -1/2 =x- 4 /-6
y - 1(-6) = 2(x - 4)
-6y + 6 = 2x -8
-6y = 2x - 8 - 6
-6y = 2x -14