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2.z=3
3.y=-9
#CMIIW
y=3z-6
substitusikan: x+2(3z-6)=-4
x+6z-12=-4
x+6z=12-4
x+6z=8
2x+z=5
x=-6z+8
substitusikan: 2(-6z+8)+z=5
-12z+16+z=5
-11z=5-16
-11z=-11
z=-11/-11
z= 1
y-3z=-6
masukkan nilai z:
y-3(1)=-6
y-3=-6
y=-6+3
y=-3
masukkan nilai y: x+2y=-4
x+2(-3)=-4
x-6=-4
x=-4+6
x=2
jadi, x=2 , y=-3, z=1