Pernyataan yang benar berkaitan dengan rangkaiaan diatas adalah....... Question from @Anderson31

November 2019 1 28 Report

Pernyataan yang benar berkaitan dengan rangkaiaan diatas adalah...

$\displaystyle R = 210\;\Omega \\ L = 1,8\;H \\ C = 16\;\mu F = 16\times10^{-6}\;F\\ V_m = 5.8 \;\text{v} \\ \omega = 250\;{}^{rad}/_s$

Penyelesaian:

$\displaystyle \begin{aligned}X_L &= \omega L \\ &= 250\cdot 1.8 \\ &= 450 \;\Omega \\ X_C &= \frac{1}{\omega C} \\ &= \frac{1}{250\cdot16\times10^{-6}} \\ &= \frac{10^5}{25\times16} \\ &= 250 \; \Omega \end{aligned}$

(1)

$\displaystyle \begin{aligned}Z &= \sqrt{R^2+(\Delta X)^2} \\ &= \sqrt{210^2+(450-250)^2} \\ &= \sqrt{210^2+200^2} \\ &= 10\cdot\sqrt{21^2+20^2} \\ &= 10\cdot\sqrt{441+400} \\ &= 10\cdot\sqrt{841} \\ &= 10\cdot29 \\ &= \boxed{\bold{290\;\Omega}}\end{aligned}\\ \therefore \boxed{\bold{(1)\;Benar}}$

(2)

$\displaystyle \begin{aligned} I_m &= \frac{V_m}{Z} \\ &= \frac{5.8}{290} \\ &= 0.02 \; A \\ &= \boxed{\bold{20\;mA}}\end{aligned} \\ \therefore \boxed{\bold{(2)\;Benar}}$

(3)

$\displaystyle X_L\dots X_C \\ 450\;\Omega\:\bold{>}\:250\;\Omega \longrightarrow \boxed{\bold{Bersifat\:induktif}} \\ \therefore \boxed{\bold{(3)\;Salah}}$

(4)

$\displaystyle \begin{aligned}I_{ef} &= \frac{I_m}{2}\sqrt{2} \\ &= \frac{0.02}{2}\sqrt{2} \\ &= 0.01\cdot\sqrt{2}\;A \\ V_{ef_{bc}} &= V_{L_{ef}} \\ &= I_{ef}\cdot X_L \\ &= 0.01\cdot\sqrt{2}\cdot450 \\ &= \boxed{\bold{4.5\sqrt{2}\;v}}\end{aligned}\\ \therefore \boxed{\bold{(4)\;Salah}}$