Question

permisi.. Mohon bantuannya, terimakasih​

Answer 1

Jawaban:

4,92 gram

Penjelasan:

larutan penyangga asam:

[H+] = Ka x mol asam / mol garam

Cari nilai [H+].

pH = 5

Maka [H+] = 10^(-5) M

cari nilai mol asam asetat

Mol asam = M x V = 0,6 x 0,1 liter = 0,06 mol

10^(-5) = 10^(-5) x 0,06 mol / mol garam

mol garam = 0,06 mol

Massa garam CH3COONa

= mol x Mr

= 0,06 mol x 82 gram/mol

= 4,92 gram