Jawaban:
a. 3×4%
3×4/100
12/100
0.12
b. Dikurangi 60 persen dari panjang semula berarti 100 persen - 60 persen =40 persen => T2/T1= √ 40 /100 => T2 = 3√40/100. => T2 = √√120 / 100. => T2 = √12 = 2√3 sekon
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Jawaban:
a. 3×4%
3×4/100
12/100
0.12
b. Dikurangi 60 persen dari panjang semula berarti 100 persen - 60 persen =40 persen => T2/T1= √ 40 /100 => T2 = 3√40/100. => T2 = √√120 / 100. => T2 = √12 = 2√3 sekon