Perhatikan persamaan reaksi redok berikut ini
Zn(s) + 2 HCl(aq)
→ ZnCl2(aq) + H2(g)
Tentukan :
Zn(s) + 2 HCl(aq)
→ ZnCl2(aq) + H2(g)
Tentukan :
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Jawaban:
a. Biloks Zn=0
b. Biloks Cl=-1
c. Biloks Zn =+2
d. Biloks H=0
e. Oksidator =HCl
f. Reduktor =Zn
g. Hasil oksidasi=ZnCl2
h. Hasil reduksi =H2