[tex] \tt = \sqrt{ {17}^{2} - {15}^{2} } [/tex]
[tex] \tt = \sqrt{289 - 225} [/tex]
[tex] \tt = \sqrt{64} [/tex]
= 8 cm (C.)
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
Jawaban:
c. 8 cm
Penjelasan dengan langkah-langkah:
BC = √AB² - AC²
= √ 17² - 15²
= √289 - 225
= √ 64
BC = 8
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[tex] \tt = \sqrt{ {17}^{2} - {15}^{2} } [/tex]
[tex] \tt = \sqrt{289 - 225} [/tex]
[tex] \tt = \sqrt{64} [/tex]
= 8 cm (C.)
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
Verified answer
Jawaban:
c. 8 cm
Penjelasan dengan langkah-langkah:
BC = √AB² - AC²
= √ 17² - 15²
= √289 - 225
= √ 64
BC = 8