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sudut acb =90 derajat (karena sdt keliling yg menghadap sudut pusat)
maka sudut bac = 180-65-90= 25 derajat
<BCA = 90° (siku-siku)
dit : <BAC?
jawab : <ABC + <BCA + <BAC = 180°
65° + 90° + <BAC = 180°
155° + <BAC = 180°
<BAC = 180° - 155°
<BAC = 25°