Jawab:
y^2 + ((12-6) : 2)^2= 5^2 = y^2 + 9 = 25
y^2= 25-9= 16 y= sqrt(16)= 4 cm= tinggi trapesium
luas permukaan= luas alas dan tutup + luas sisi yg lain
= ((12+6) x 4) + (12 x 15 + 6 x 15 + (2 x 5 x 15))
= (18 x 4)+ (180 + 90 + 150)= 72 + 420= b. 492 cm2
maaf kalo saya salah ya...
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Jawab:
y^2 + ((12-6) : 2)^2= 5^2 = y^2 + 9 = 25
y^2= 25-9= 16 y= sqrt(16)= 4 cm= tinggi trapesium
luas permukaan= luas alas dan tutup + luas sisi yg lain
= ((12+6) x 4) + (12 x 15 + 6 x 15 + (2 x 5 x 15))
= (18 x 4)+ (180 + 90 + 150)= 72 + 420= b. 492 cm2
maaf kalo saya salah ya...