Diketahui:
AOE = 150°
BED = 35°
Ditanyakan:
ACE
Jawab:
AOE = 150° -> sudut pusat.
karena ADE dan EBA sudut keliling dari busur yg sama, maka:
ADE = EBA = 1/2. 150° = 75°
DFE+BED+ADE = 180°
DFE+35°+75° = 180°
DFE+110° = 180°
DFE = 180°-110°
DFE = 70°
karena BFA dan DFE sudut yg saling berlawanan, maka:
BFA = DFE = 70°
FAB+BFA+EBA = 180°
FAB+70°+75° = 180°
FAB+145° = 180°
FAB = 180°-145°
FAB = 35°
ADC+ADE = 180°
ADC+75° = 180°
ADC = 180°-75°
ADC = 105°
ACE+ADC+FAB = 180°
ACE+105°+35° = 180°
ACE+140° = 180°
ACE = 180°-140°
ACE = 40° (A)
Mapel: Matematika
Kelas: 8
Materi: Lingkaran
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Diketahui:
AOE = 150°
BED = 35°
Ditanyakan:
ACE
Jawab:
AOE = 150° -> sudut pusat.
karena ADE dan EBA sudut keliling dari busur yg sama, maka:
ADE = EBA = 1/2. 150° = 75°
DFE+BED+ADE = 180°
DFE+35°+75° = 180°
DFE+110° = 180°
DFE = 180°-110°
DFE = 70°
karena BFA dan DFE sudut yg saling berlawanan, maka:
BFA = DFE = 70°
FAB+BFA+EBA = 180°
FAB+70°+75° = 180°
FAB+145° = 180°
FAB = 180°-145°
FAB = 35°
ADC+ADE = 180°
ADC+75° = 180°
ADC = 180°-75°
ADC = 105°
ACE+ADC+FAB = 180°
ACE+105°+35° = 180°
ACE+140° = 180°
ACE = 180°-140°
ACE = 40° (A)
Mapel: Matematika
Kelas: 8
Materi: Lingkaran