Penjelasan dengan langkah-langkah:
[tex] \\ \\ \\ \\ \\ \\ \\ \\ [/tex]
BC² = AC² + AB²
BC² = 16² + 12²
BC = √256 + 144
BC = √400 +
BC = 20
1/2 × a × t
AB . AC = BC . AD
12 . 16 = 20 . AD
AD = 20 . 16 / 20
AD = 9,6
Opsi B.9,6
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
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Verified answer
Penjelasan dengan langkah-langkah:
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[tex] \\ \\ \\ \\ \\ \\ \\ \\ [/tex]
Panjang BC :
BC² = AC² + AB²
BC² = 16² + 12²
BC = √256 + 144
BC = √400 +
BC = 20
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Luas :
1/2 × a × t
AB . AC = BC . AD
12 . 16 = 20 . AD
AD = 20 . 16 / 20
AD = 9,6
Opsi B.9,6
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
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