Question

Perhatikan gambar diatas. Apabila hambatan lampu satu 3 Ohm, lampu dua 6 Ohm, lampu tiga 9 Ohm dan lampu empat 12 Ohm, sementara hambatan kawat diabaikan. Tentukan :

a. Hambatan total rangkaian

b. Besar tegangan pada masing-masing lampu

c. Kuat arus yang melalui masing-masing lampu

Tolong Bantu Jawab....​

Answer 1

Jawaban:

Penjelasan:
R1 = 3 ohm
R2 = 6 ohm
R3 = 9 ohm
R4 = 12 ohm

1) Hambatan total
1/Rparalel = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/Rparalel = 1/3 + 1/6 + 1/9 + 1/12
1/Rparalel = 12/36 + 6/36 + 4/36 + 3/36
1/Rparalel = 12+6+4+3/36
1/Rparalel = 26/36
Rparalel = 36/26 = 1,38 ohm

2) Besar tegangan masing"
i = V/R
i = 12/1,38 = 8,6 A

V1 = i.R1=8,6.3 = 25,8 volt
V2 = i.R2 = 8,6.6= 51,6 volt
V3 = i.R3 = 8,6.9 = 77,4 volt
V4 = i.R4 = 8,6.12 = 103,2 volt

3) arus masing"
i1 = V/R1 = 12/3 = 4 ampere
i2 = V/R2 = 12/6 = 2 ampere
i3 = V/R3 = 12/9 = 1,33 ampere
i4 = V/R4 = 12/12 = 1 ampere