Diameter kerucut
[tex] \sqrt{V \div (\frac{t}{12} \times \pi)} \\ \sqrt{401,92 \div ( \frac{6}{12} \times 3,14) } \\ \sqrt{401,92 \div 1,57} \\ \sqrt{256} = 16 \: cm \: (A)[/tex]
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Diameter kerucut
[tex] \sqrt{V \div (\frac{t}{12} \times \pi)} \\ \sqrt{401,92 \div ( \frac{6}{12} \times 3,14) } \\ \sqrt{401,92 \div 1,57} \\ \sqrt{256} = 16 \: cm \: (A)[/tex]