Question

Perbandingan senilai
Tentukan nilai t yang memenuhi perbandingan senilai berikut ini !
a. (t – 3) : (t – 2) = 2 : 3
b. 6 : (t + 3) = 4 : (t – 2)
c. (t – 2) : (t + 2) = 1 : 3
d. t : (t + 1) = (t – 1) : (t – 4)

Answer 1

1.)
dikali silang jadi,
3(t-3) = 2(t-2)
3t-9 = 2t-4
3t-2t = 9-4
t=5

2.)
dikali silang jadi,
6(t-2) = 4(t+3)
6t-12 = 4t+12
6t-4t = 12+12
2t = 24
t = 12

3.)
dikali silang jadi,
3(t-2) = t+2
3t-6 = t+2
3t-t = 6+2
2t = 8
t = 4

4.)
dikali silang jadi,
t(t-4) = (t-1)(t+1)
t²-4t =t²-1
t²-t²-4t = -1
-4t = -1
t = -1/-4
t = 1/4

semoga membantu

Answer 2

A.  t = 5
b. 6 / ( t + 3) = 4 / (t-2)
    6 ( t-2) = 4 ( t + 3)
     6t -12 = 4t + 12
     2t = 24...t = 12 
c. (t - 2) / ( t + 2) = 1/3
    3t - 6 = t + 2
     2t = 8 .....T = 4
d. t / ( t + 1) =  (t-1) / (t-4)
    t ( t-4) = (t + 1) ( t-1)
     t² - 4t = t² -t + t -1
     t²-t² - 4t = -1
          -4t = -1
            t = 1/4