" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
p=4x
l=3x
t=2x
luas alas balok = p · l
108 =4x · 3x
108 =12x²
108/12=x²
9 =x²
√9 =x
3 =x
maka diperoleh
panjang 4x =4(3)=12 cm
lebar 3x =3(3)=9 cm
tinggi 2x =2(3)=6 cm
Luas permukaan balok
=2 (p·l + p·t + l·t)
=2 (12·9 + 12·6 + 9·6)
=2 (108 + 72 + 54 )
=2 (234)
=468 cm²
p = 4n , l = 3n , dan t = 2n
La balok = 108
p.l = 108
4n.3n = 108
12n² = 108
n² = 108/12
n² = 9
n = √9
n = 3
maka,
p = 4n = 4.3 = 12 cm
l = 3n = 3.3 = 9 cm
t = 2n = 2.3 = 6 cm
jadi,
Lp balok
= 2(pl+pt+lt)
= 2(12.9 + 12.6 + 9.6)
= 2(108 + 72 + 54)
= 2(234)
= 468 cm²