Question

1. (1/49v7)^-1/3=....
2. (1/27v3)^1/5=.....
3. 6+v3(4-2v3)=......
4. Nilai n yang memenuhi persamaan: 2nv2-3= 3n/v2+1 adalah....
5. Diketahui 1/x= 3+v3 dan 1/y= 2v3+2, maka x/y sama dengan ....

NB: /= per, v= akar, ^= pangkat, tolong ya^^

Answer 1

1. (1/49√7)^(1/3)
= (1/7^(5/2))^(1/3)
= 7^(-5/2 x 1/3)
= 7^(-5/6)

2. (1/27√3)^(1/5)
= (1/3^(7/2))^(1/5)
= 3^(-7/2 x 1/5)
= 3^(-7/10)

3. 6 + √3 (4 - 2√3)
= 6 + 4√3 - 6
= 4√3

4. 2n√2 - 3 = 3n/(√2 + 1)
⇒ (2n√2 - 3)(√2 + 1) = 3n
4n + 2n√2 - 3√2 - 3 = 3n
n + 2n√2 - 3√2 - 3 = 0
n(1 + 2√2) = 3 + 3√2
n = (3 + 3√2)/(1 + 2√2)
= (3 + 3√2)(1 - 2√2) / (1 - 8)
= (3 - 3√2 - 12) / -7
= (-9 - 3√2)/-7
= (9 + 3√2)/7

5. 1/x = 3 + √3
1/y = 2√3 + 2

1/y : 1/x = x/y
(2√3 + 2)/(3 + √3) = x/y
(2√3 + 2)(3 - √3)/(9 - 3) = x/y
(6√3 - 6 + 6 - 2√3) = x/y
4√3 = x/y

semoga membantu ^^