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jawab :
2a(1)+b(2)=10 10(1)-2a(2)=-b
2a+2b=10 10-4a=-b --> -4a+b=-10
*eliminasi
2a+2b=10 lx2l 4a+4b=20
-4a+b=-10 lx1l -4a+b=-10
__________+
5b = 10
b = 2
*substitusi
2a+2(2)=10
2a = 6
a = 3
jadi, a=3 b =2
2a + 2b: 10 dan 10-4a: -b
》2a + 2b - 10 (1)
》10 - 4a + b (2)
(1) + (2) =
-2a + 3b: 0 (3)
(3) + (1) =
5b: 10
b = 2
Masukan b = 2 ke (3),
-2a + 6: 0
a = 3
Jadi, a = 3 dan b = 2