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3(x+y=2)
3x+3y=6
3x+2y=6
------------eliminasi
y = 0
x + y = 2
x + 0 = 2
x = 2
3x + 2y = 6 ⇒ dikali 1 ⇒ 3x + 2y = 6
x + y = 2 ⇒ dikali 3 ⇒ 3x + 3y = 6 _
-y = 0
y = 0
subtitusi ⇒
x + y = 2
⇔x + 0 = 2
⇔x = 2