Jawab:
∛(8^(x+1)) = (8^(x+1))^(1/3)=8^((x+1)/3)=2^(3.(x+1)/3)=2^(x+1)
(1/4)^(x²-1)=(2^(-2))^(x²-1)=(2^(-2))^((x-1).(x+1))=2^(2.(x+1)(x-1))
∛(8^(x+1)) = (1/4)^(x²-1)
∛(8^(x+1)) : (1/4)^(x²-1) = 1
2^(x+1) : 2^(-2.(x-1).(x+1))= 1
2^(x+1) . 2^(2.(x-1).(x+1)) = 1
2^(x+1) . 2^(2.(x²-1)) =1
2^(2x²-2+x-1) =1
2^(2x²+x-3)=1
2^(2x+3)(x-1)=1
maka supaya 2^(2x+3)(x-1)=1 atau 2^0=1
jadi (2x+3)(x-1)=0
jadi x = -3/2 atau 1
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Jawab:
∛(8^(x+1)) = (8^(x+1))^(1/3)=8^((x+1)/3)=2^(3.(x+1)/3)=2^(x+1)
(1/4)^(x²-1)=(2^(-2))^(x²-1)=(2^(-2))^((x-1).(x+1))=2^(2.(x+1)(x-1))
∛(8^(x+1)) = (1/4)^(x²-1)
∛(8^(x+1)) : (1/4)^(x²-1) = 1
2^(x+1) : 2^(-2.(x-1).(x+1))= 1
2^(x+1) . 2^(2.(x-1).(x+1)) = 1
2^(x+1) . 2^(2.(x²-1)) =1
2^(2x²-2+x-1) =1
2^(2x²+x-3)=1
2^(2x+3)(x-1)=1
maka supaya 2^(2x+3)(x-1)=1 atau 2^0=1
jadi (2x+3)(x-1)=0
jadi x = -3/2 atau 1