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U4 = a + r^3 = 40
U6 = a + r^5 = 160
ar^5 = 160
ar^3 = 40
atas bagi bawah
r^2 = 4
r = 2
ar^3 = 40
a2^3 = 40
8a = 40
a = 5
U1 = 5
U4 = ar^3 = 40
U6 = ar^5 = 160
maka ar^5/ ar^3= 160/40 -> r^2 = 4 dan r = 2
U4 = a2^3 = 40
8a = 40 dan a = 5
Jadi, suku pertama barisan geometri tersebut adalah 5