Jawaban:
[tex] \sf 3(3x - \frac{2}{3} ) > 4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 3(3x - \frac{2}{3} )[/tex]
[tex] \sf = 9x - \frac{6}{3} [/tex]
[tex] \sf = \red{9x - 2 }[/tex]
[tex] \sf 3(3x - \frac{2}{3} ) >4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 8x + \frac{4}{2} [/tex]
[tex] \sf = \red{8x + 2}[/tex]
[tex] \sf 3(3x - \frac{2}{3} ) > 4(2x + \frac{1}{2} ) \\ \sf 9x - \frac{6}{3} > 8x + \frac{4}{2} \\ \sf 9x - 2 > 8x + 2 \\ \sf 9x - 8x > 2 + 2 \: \: \: \: \\ \: \: \: \: \: \: \: \: \sf x > 2 + 2 \\ \sf \red{x > 4}[/tex]
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Jawaban:
Hasil perkalian ruas kiri
[tex] \sf 3(3x - \frac{2}{3} ) > 4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 3(3x - \frac{2}{3} )[/tex]
[tex] \sf = 9x - \frac{6}{3} [/tex]
[tex] \sf = \red{9x - 2 }[/tex]
Hasil perkalian ruas kanan
[tex] \sf 3(3x - \frac{2}{3} ) >4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 4(2x + \frac{1}{2} )[/tex]
[tex] \sf = 8x + \frac{4}{2} [/tex]
[tex] \sf = \red{8x + 2}[/tex]
Himpunan penyelesaian
[tex] \sf 3(3x - \frac{2}{3} ) > 4(2x + \frac{1}{2} ) \\ \sf 9x - \frac{6}{3} > 8x + \frac{4}{2} \\ \sf 9x - 2 > 8x + 2 \\ \sf 9x - 8x > 2 + 2 \: \: \: \: \\ \: \: \: \: \: \: \: \: \sf x > 2 + 2 \\ \sf \red{x > 4}[/tex]
'조슈아' (Svt)