Explicación paso a paso:
Solución !
A)
[tex] \sqrt{( \frac{9}{8} } ) ^{2} = [/tex]
[tex] \sqrt{ \frac{ {9}^{2} }{ {8}^{2} } } = [/tex]
[tex] \sqrt{ \frac{81}{64} } = [/tex]
[tex] = \frac{9}{8} [/tex]
B)
[tex] \sqrt{( \frac{4}{3} } ) ^{6} [/tex]
[tex] = \sqrt{ \frac{ {4}^{6} }{ {3}^{6} } } [/tex]
[tex] = \sqrt{ \frac{4096}{729} } [/tex]
[tex] = \frac{64}{27} [/tex]
C)
[tex] = \sqrt[3]{( \frac{2}{7} ) ^{9} } [/tex]
[tex] = \sqrt[3]{ \frac{ {2}^{9} }{ {7}^{9} } } [/tex]
[tex] = \sqrt[3]{ \frac{512}{40353607} } [/tex]
[tex] = \frac{ \sqrt[3]{512} }{ \sqrt[3]{40353607} } [/tex]
[tex] = \frac{8}{343} [/tex]
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Verified answer
Explicación paso a paso:
hole °
Solución !
A)
[tex] \sqrt{( \frac{9}{8} } ) ^{2} = [/tex]
[tex] \sqrt{ \frac{ {9}^{2} }{ {8}^{2} } } = [/tex]
[tex] \sqrt{ \frac{81}{64} } = [/tex]
[tex] = \frac{9}{8} [/tex]
B)
[tex] \sqrt{( \frac{4}{3} } ) ^{6} [/tex]
[tex] = \sqrt{ \frac{ {4}^{6} }{ {3}^{6} } } [/tex]
[tex] = \sqrt{ \frac{4096}{729} } [/tex]
[tex] = \frac{64}{27} [/tex]
C)
[tex] = \sqrt[3]{( \frac{2}{7} ) ^{9} } [/tex]
[tex] = \sqrt[3]{ \frac{ {2}^{9} }{ {7}^{9} } } [/tex]
[tex] = \sqrt[3]{ \frac{512}{40353607} } [/tex]
[tex] = \frac{ \sqrt[3]{512} }{ \sqrt[3]{40353607} } [/tex]
[tex] = \frac{8}{343} [/tex]
Atte ° David