Question

Panjang sisi sejajar dari trapesium (2p+5)cm dan (4p+1)cm,luasnya (6p2+13p+6)cm2.
a.nyatakan tinggi trapesium dengan p
b.hitung tingginya,bila p=9

Answer 1

L=(a+b).t/2
6p2+13p+6=((2p+5)+(4p+1)).t/2
6p2+13p+6=(8p2+2p+20p+5).t/2 --> x2
2(6p2+13p+6)=8p2+22p+5.t
12p2+26p+12=8p2+22p+5.t
12p2+26p+12/8p2+22p+5=t
trs gw bingung lg gmn caranya .__. maafkan dirikuu cuma bisa bantu ampe situ :(

Answer 2

A. L = (a + b) × t / 2
(6p² + 13p + 6) = [(2p + 5) + (4p + 1)] × t / 2
(6p² + 13p + 6) = (6p + 6) × t / 2
(6p² + 13p + 6) × 2 = (6p + 6) × t
12p² + 26p + 12 = (6p + 6) × t
t = 12p² + 26p + 12 : 6p + 6
t = 2p + 26p + 2
t = 28p + 2

b. t = 28p + 2 = 28 (9) + 2 = 254cm