•°• Panjang siku-siku segitiga adlh 4x cm dan 3x cm. Jika panjang sisi hipotenusanya 35 cm, maka luas segitiga tsbt adlh [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]
[tex] \\ \\ [/tex]
Penjelasan dengan langkah-langkah:
[tex] \\ \: [/tex]
Tentukan x nya
[tex]\sf{a² + b²}[/tex] = [tex]\sf{c²}[/tex]
[tex]\sf{4x² + 3x²}[/tex] = [tex]\sf{35²}[/tex]
[tex]\sf{16x² + 9x²}[/tex] = [tex]\sf{1.225}[/tex]
[tex]\sf{25x²}[/tex] = [tex]\sf{1.225}[/tex]
[tex]\sf{x²}[/tex] = [tex]\sf{\dfrac{1.225}{25}}[/tex]
[tex]\sf{x²}[/tex] = [tex]\sf{49}[/tex]
[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{49}}[/tex]
[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{7²}}[/tex]
[tex]\sf{x}[/tex] = [tex]\underline{\boxed{\bf{7}}}[/tex]
Maka, nilai x nya adlh 7
Subtituskan x
a = 4x
a = 4(7)
a = [tex]\underline{\boxed{\bf{28~cm}}}[/tex]
[tex] \: [/tex]
b = 3x
b = 3(7)
b = [tex]\underline{\boxed{\bf{21~cm}}}[/tex]
Jadi, nilai a dan b adlh 28 cm dan 21 cm
Jika semua sdh ketemu,barulah menentukan luas segitiganya
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{½ × a × t}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{\bcancel{½} × \bcancel{28}⁴ × 21}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{4 × 21}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]
[tex]_________________________________________________________________________________________________________________________[/tex]
[tex] \\ \\ \\ \\ \\ [/tex]
=====
[tex]\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}[/tex]
[tex]\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}[/tex]
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•°• Panjang siku-siku segitiga adlh 4x cm dan 3x cm. Jika panjang sisi hipotenusanya 35 cm, maka luas segitiga tsbt adlh [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]
[tex] \\ \\ [/tex]
Penjelasan dengan langkah-langkah:
[tex] \\ \: [/tex]
Tentukan x nya
[tex]\sf{a² + b²}[/tex] = [tex]\sf{c²}[/tex]
[tex]\sf{4x² + 3x²}[/tex] = [tex]\sf{35²}[/tex]
[tex]\sf{16x² + 9x²}[/tex] = [tex]\sf{1.225}[/tex]
[tex]\sf{25x²}[/tex] = [tex]\sf{1.225}[/tex]
[tex]\sf{x²}[/tex] = [tex]\sf{\dfrac{1.225}{25}}[/tex]
[tex]\sf{x²}[/tex] = [tex]\sf{49}[/tex]
[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{49}}[/tex]
[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{7²}}[/tex]
[tex]\sf{x}[/tex] = [tex]\underline{\boxed{\bf{7}}}[/tex]
Maka, nilai x nya adlh 7
[tex] \\ \: [/tex]
Subtituskan x
a = 4x
a = 4(7)
a = [tex]\underline{\boxed{\bf{28~cm}}}[/tex]
[tex] \: [/tex]
b = 3x
b = 3(7)
b = [tex]\underline{\boxed{\bf{21~cm}}}[/tex]
Jadi, nilai a dan b adlh 28 cm dan 21 cm
[tex] \\ \: [/tex]
Jika semua sdh ketemu,barulah menentukan luas segitiganya
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{½ × a × t}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{\bcancel{½} × \bcancel{28}⁴ × 21}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{4 × 21}[/tex]
[tex]\sf{L_{Segitiga}}[/tex] = [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]
[tex] \\ \\ [/tex]
[tex]_________________________________________________________________________________________________________________________[/tex]
[tex] \\ \\ \\ \\ \\ [/tex]
=====
[tex]\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}[/tex]
[tex] \: [/tex]
[tex]\colorbox{black} { \blue{ \boxed{ \boxed{\rm\color{FF6666}{༆@}\color{FFB266}{O}\color{B2FF66}{n}\color{66FF66}{l}\color{66FFFF}{y}\color{66B2FF}{Y}\color{6666FF}{o}\color{B266FF}{o}\color{FF66FF}{j}\color{FF66B2}{i}\color{FF9999}{n}\color{FFCC99}{࿐}}}}}[/tex]