Question

Panjang siku-siku segitiga adalah 4x cm dan 3x cm. Jika panjang sisi hipotenusanya 35 cm. Berapakah luas segitiga tersebut?​

Answer 1

•°• Panjang siku-siku segitiga adlh 4x cm dan 3x cm. Jika panjang sisi hipotenusanya 35 cm, maka luas segitiga tsbt adlh [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]

[tex] \\ \\ [/tex]

Penjelasan dengan langkah-langkah:

• a = 4x cm
• b = 3x cm
• c = 35 cm

[tex] \\ \: [/tex]

Tentukan x nya

[tex]\sf{a² + b²}[/tex] = [tex]\sf{c²}[/tex]

[tex]\sf{4x² + 3x²}[/tex] = [tex]\sf{35²}[/tex]

[tex]\sf{16x² + 9x²}[/tex] = [tex]\sf{1.225}[/tex]

[tex]\sf{25x²}[/tex] = [tex]\sf{1.225}[/tex]

[tex]\sf{x²}[/tex] = [tex]\sf{\dfrac{1.225}{25}}[/tex]

[tex]\sf{x²}[/tex] = [tex]\sf{49}[/tex]

[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{49}}[/tex]

[tex]\sf{x}[/tex] = [tex]\sf{\sqrt{7²}}[/tex]

[tex]\sf{x}[/tex] = [tex]\underline{\boxed{\bf{7}}}[/tex]

Maka, nilai x nya adlh 7

[tex] \\ \: [/tex]

Subtituskan x

a = 4x

a = 4(7)

a = [tex]\underline{\boxed{\bf{28~cm}}}[/tex]

[tex] \: [/tex]

b = 3x

b = 3(7)

b = [tex]\underline{\boxed{\bf{21~cm}}}[/tex]

Jadi, nilai a dan b adlh 28 cm dan 21 cm

[tex] \\ \: [/tex]

Jika semua sdh ketemu,barulah menentukan luas segitiganya

[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{½ × a × t}[/tex]

[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{\bcancel{½} × \bcancel{28}⁴ × 21}[/tex]

[tex]\sf{L_{Segitiga}}[/tex] = [tex]\sf{4 × 21}[/tex]

[tex]\sf{L_{Segitiga}}[/tex] = [tex]\underline{\boxed{\red{\bf{294~cm²}}}}[/tex]

[tex] \\ \\ [/tex]

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[tex] \\ \\ \\ \\ \\ [/tex]

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[tex] \: [/tex]

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