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ΔPSR sebangun dengan ΔPRQ
Jad, dapat dibuat perbandingan :
6(6+x) = 144
36 + 6x = 144
6x = 144-36
6x = 108
x = 12
a) PQ = 6+x
PQ = 6+12
= 18 cm
ΔPSR sebangunn dengan ΔRSQ
maka mencari RS dengan perbandingan
*dengan SQ = PQ-PS
SQ = 18 - 6 = 12 cm
x² = 108
x = √108
x = √36×3
x = 6√3 cm
b) RS = 6√3 cm
Semoga membantu :)
PR² = PS × PQ
12² = 6 × PQ
144 = 6 PQ
PQ = 144/6
PQ = 24 cm
SQ = 24 - 6 = 18 cm
b)
RS² = PS × SQ
RS² = 6 × 18
RS² = 108
RS = √108
RS = 6√3 cm