Question

panjang PQ = 16cm
QR = 12 cm
luas daerah yg di arsir adalah?​

Answer 1

[tex]d = diameter \\ \sqrt{ {PQ}^{2} + {QR}^{2} } = \sqrt{ {16}^{2} + {12}^{2} } \\ \sqrt{256 + 144} = \sqrt{400} = 20 \\ r = d \div 2 = 20 \div 2 = 10 \\ \\ Luas \: daerah \:yg \: diarsir \\ (\pi \times r \times r) - (p \times l) \\ (3,14 \times 10 \times 10) - (16 \times 12) \\ 314 - 192 \\ 122 \: {cm}^{2} [/tex]