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12² = AB² - (9-4)²
144 = AB² - 25
AB² = 144+25
AB² = 169
AB = √169
= 13 cm
12² = J ² - ( 9 - 4 )²
12² = J² - 5²
144 = J² - 25
144 + 25 = J²
169 = J ²
√169 = J
13 = J
jadi jarak kedua pusat lingkaran adalah 13 cm.
semogamembantu . tandaiterbaikya!!!!