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panjang tali terpanjang = U10 = a+9b =155 (2)
kita subtitusikan nilai a ke (2)
9b=135
b= 15
ditanya panjang pita semula?
panjang pita semula diperoleh dari panjang bagian 1 -10 , artinya jumlah deret 1-10
S10 = 10/2 (2a+9b)
S10 = 5(2x20+9x15)
S10 = 875 cm