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Verified answer
LogAritMa5][
f(x) = 2^x
f(²log 5) = 2^(²log 5) = 5
6][
²log (14 + 3^(3²'log 2²))
= ²log (14 + 2)
= ²log 2⁴
= 4
7][
4^(√2 log x) = 3⁴
2^((2/(1/2)) . 2'log x) = 3⁴
x⁴ = 3⁴
x = 3
x'log 27 = 3'log 3³ = 3